the answer given in my book is 4b-3b=6+4, b= 10. but my conclusion is 4b-3b=-4+6, = -10. when do i apply positive, and when for negative?
tx for responding to my math problem. the original problem is:-
Given the formula D/B = d+b/d-2b,
a) find B when d=1, b=3 and D=4
b) find b when B=3, D= -2 and d=2
This is how I would do them.
4/B = 1 + 3/1 - 2*3
Remember to do all the multiplication first.
4/B = 1 + 3/1 - 6
3/1 is the same as 3 so rewrite as
4/B = 1 + 3 - 6
Now do your addition and subtraction from left to right
4/B = -2
Undo division with multiplication
4 = -2B
Undo multiplication with division
4/(-2) = B
-2 = B because a positive divided by a negative is a negative.
Apr 23 '10
For the second equation...
-2/3 = 2 + b/2 - 2*b
I would eliminate the fractions by multiplying by the common denominator , in this case 6, on both sides of the equal sign.
6(-2/3) = (2 + b/2 - 2*b)6
By doing that you have a much simpler equation to work with.
-4 = 12 + 3b - 12b
Now it is easier to combine the like terms,3b - 12b.
This will give you the equation
-4 = 12 - 9b
Subtract 12 from both sides of the equal sign.
and you have
-16/(-9) = b
simplify your negatives and you get
I hope this helps...let me know if you need more information.
What was the original problem?????