The angle of elevation of the top of the Barasoain church in Bulacan is 20degrees. If an observer is 102meters from the church, how high is the church?

Expert Answers
embizze eNotes educator| Certified Educator

Draw a right triangle with one leg labeled 102m, and the other leg labeled `h` . The acute angle adjacent to the side 102m is `20^@` .

The height `h` is found using the tangent function. The tangent is defined as the side opposite the acute angle over the side adjacent or `tan alpha=("opposite"}/{"adjacent")`

So `tan 20^@=h/102==>h=102tan20^@`

Then `h~~37.12`

----------------------------------------------------------------

The height of the church is approximately 37m

----------------------------------------------------------------