The angle of elevation of the top of a tree from a point 50 feet from it's base is 30 degrees . What is the height of the tree.

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The angle of elevation from a point 50 feet from the base of the tree to the top of the tree is 30 degrees.

Now tan 30 = height of tree/ distance of the point from the base

=> tan 30 = H / 50

=> 1/ sqrt 3 =...

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The angle of elevation from a point 50 feet from the base of the tree to the top of the tree is 30 degrees.

Now tan 30 = height of tree/ distance of the point from the base

=> tan 30 = H / 50

=> 1/ sqrt 3 = H / 50

=> H = 50/sqrt 3

=> 28.86 feet

The height of the tree is 28.86 feet.

Approved by eNotes Editorial Team