If an object is thrown vertically upward with an initial velocity of v, from an original position of s, the height h at any time t is given by: h = 16t^2 + vt + s. (Where h and s are in feet, t is in seconds and v is in ft/sec).
A ball is thrown upward with initial velocity of 96 ft/sec from the top of a 100 ft bridge. Determine the time that it takes for the ball to get to a height of 200 ft from the ground.
Round answers to two decimals, separated by a comma.
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u= 96 ft/sec
s=100 ft (height of the top of bridge)
h= 200 ft (from ground)
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