An object is thrown downward with an initial (t = 0) speed of 10 m/s from a height of 60 m above the ground. At the same instant (t = 0), a second object is propelled vertically upward from ground level with a speed of 40 m/s. At what height above the ground will the two objects pass each other?

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The height of the first object is given by

`h1(t) = 60 - 10*t - (g*t^2)/2` ,

where 60 is the initial height, -10 is the initial downward speed and g is gravity acceleration, g=`9.8m/s^2` .

The height of the...

(The entire section contains 112 words.)

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