An object is released from rest on a planet that has no atmosphere. The object falls freely for 3 m in the first second. What is the magnitude of the acceleration due to gravity on the planet?

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The equation of motion that can be used to describe the fall of this object is

`d = v_0t + at^2/2` .

Here, d is the distance that the object fell in time t , and a is the acceleration due to the gravity of the planet. Since there is...

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The equation of motion that can be used to describe the fall of this object is

`d = v_0t + at^2/2` .

Here, d is the distance that the object fell in time t, and a is the acceleration due to the gravity of the planet. Since there is no atmosphere, the gravity is the only force the object will experience, so the gravity is the only force providing this acceleration.

Since the object in this case falls from rest, initial velocity `v_0 =0` . Then the equation motion becomes

`d = at^2/2` .

From here, the acceleration due to gravity can be found:

`3 = a*1^2/2`

`a = 6 m/s^2`

The acceleration of the free fall, or the acceleration due to gravity on this planet is 6 m/s^2.

 

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