An object is located to the left of a convex mirror whose focal length is -31 . The magnification produced by the mirror is = 0.35.
To decrease the magnification to 0.26, the object is moved further away from the mirror. Calculate the distance through which the object should be moved.
1 Answer | Add Yours
The relation between the distance of the object do, distance of the image di and the focal length is 1/do + 1/di = 1/f. The magnification is given by m = -di/do.
Here, the magnification of the object when it is placed in front of the mirror is 0.35. If the object distance is denoted by do, we have 1/do + 1/di = -1/31.
0.35 = -di/do
=> di = -0.35*do
1/do - 1/0.35*do = -1/31
=> do = 13*31/7
Using the procedure used above, if the magnification has to be made 0.26 we have 1/do - 1/0.26*do = -1/31
=> do = 37*31/13
Therefore the object has to be moved a distance 37*31/13 - 13*31/7 = 2790/91
The distance that the object has to be moved away from the mirror is approximately 30.65
We’ve answered 319,865 questions. We can answer yours, too.Ask a question