# An ideal gas has an initial pressure of 1216 mmhg at T=-23 degrees celsius and occupies a volume of 400 mL. What is the final temperature of the gas (in degrees Kelvin) if it occupies 1.20 liters...

An ideal gas has an initial pressure of 1216 mmhg at T=-23 degrees celsius and occupies a volume of 400 mL.

What is the final temperature of the gas (in degrees Kelvin) if it occupies 1.20 liters at P=0.80 ATM?

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### 1 Answer

Initial pressure , P1 = 1216 mmHg = 1.6 atm

Initial tepmerature, T1 = -23 C = 250 K

Initial volume, V1 = 0.4 litres

Final pressure , P1 = 0.8 atm

Final tepmerature, T1 = ???

Final volume, V1 = 1.2 litres

For an ideal gas, PV = nRT

nR = PV/T

for two cases,

nR = P1V1/T1 = P2V2/T2

(1.6 x 0.4 / 250) = (0.8 x 1.2/T2)

Here, you dont need to worry about the units because they will cancel out.

T2 = 375 K.

The final temperature of gas is 375 K