In an experiment, 6.500g of hydrogen sulfide is fully decomposed into its elements. If 0.384 g of hydrogen are obtained in this experiment how many grams of sulfur must be obtained, what law is...

In an experiment, 6.500g of hydrogen sulfide is fully decomposed into its elements. 

If 0.384 g of hydrogen are obtained in this experiment how many grams of sulfur must be obtained, what law is demostrated by this, and how is it explained by Dalton's atomic theory?

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jeew-m | College Teacher | (Level 1) Educator Emeritus

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From the law conservation of mass

mass of H_2S = mass of hydrogen + mass of sulphur

 

Mass of sulphur = mass of H_2S-mass of hydrogen

                        = 6.500g-0.384g

                        = 6.116g

 

So mass of sulphur = 6.116g

The law is conservation of mass.

 

In Doltans atomic theory he sates;

  • All atoms of a given element are identical in mass and properties.

(all hydrogen in `H_2S` have same mass per atom and all S in `H_2S` have same mass per atom)

 

  • Compounds are formed by a combination of two or more different kinds of atoms.

(`H_2S` is formed by H and S)

 

  • A chemical reaction is a rearrangement of atoms.

(`H_2S` is formed by a chemical reaction of H and S and the arrangement of atoms will be changed in this reaction)

 

 

Sources:

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