An empty 240 kg elevator accelerates upward at 1.4 m/s^2. The acceleration of gravity is 9.8 m/s^2.What is the tension in the cable that lifts the elevator cab? Answer in units of N.

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krishna-agrawala | College Teacher | (Level 3) Valedictorian

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Tension in the cable is equal to the force due to action of acceleration due to gravity plus the force for accelerating the elevator further by 1.4 m/s.

Thus tension in cable =

(Mass of elevator)*(accelaration due to gravity + upward accelaeartion of elevator)

= 240*(9.8 + 1.4) = 240*11.2 = 2688 N

Answer: Tension in cable is 2688 N

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