# An elevator weighing 2.00 x 10^5 N is supported by a steel cable. What is the tension in the cable when the elevator is accelerated upward at a rate of 3.00 m/s^2? (g=9.81 m/s^2) The tension in the cable is the net force by which it pulls the elevator. The result of the tension T in the cable to which an elevator is attached is the acceleration of the elevator in an upward direction. The force of gravity acting downwards accelerates the elevator by...

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The tension in the cable is the net force by which it pulls the elevator. The result of the tension T in the cable to which an elevator is attached is the acceleration of the elevator in an upward direction. The force of gravity acting downwards accelerates the elevator by 9.8 m/s^2. If the net acceleration of the elevator due to the pull of the steel cable is 3 m/s^2 upwards, the actual acceleration towards the top is 3 + 9.81 = 12.81 m/s^2.

This implies a force equal to 2*10^5*12.81 acting on the elevator in the upwards direction. This force results in a tension equal to 2562 kN in the cable.

The required tension in the cable is 2562 kN.

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