An elevator is accelerating upward at 3.0 m/s^2. A 60kg student is standing stop a spring in the elevator. How much is the spring compressed? The spring constant is 2.5 X 10^3 N/m

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A spring with a spring constant k is compressed by a length L = F/k when a force F is applied on it.

In your question the student is standing on a spring with a spring constant of 2.5 X 10^3 N/m. The elevator is moving upwards with an acceleration...

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A spring with a spring constant k is compressed by a length L = F/k when a force F is applied on it.

In your question the student is standing on a spring with a spring constant of 2.5 X 10^3 N/m. The elevator is moving upwards with an acceleration of 3 m/s^2 and the acceleration due to gravity is 9.8 m/s^2 acting downwards. The net acceleration of the student with respect to the spring is (3 + 9.8) = 12.8 m/s^2.

The force applied on the spring is 60*12.8 N

The length it is compressed by can be determined by solving 60*12.8 = 2.5*10^3*L for L

L = 60*12.8/2.5*10^3 = 0.3072

The spring is compressed by 0.3072 m

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