An electric lift makes 14 double journeys per hour. A load of 5 tonne is raised by it through a height 50m and it returns empty. The weight of the cage is half a tonne and its counterweight is 2...
An electric lift makes 14 double journeys per hour. A load of 5 tonne is raised by it through a height 50m and it returns empty.
The weight of the cage is half a tonne and its counterweight is 2 tonne. The efficiency of the hoist is 90% and that of the motor is 87%.
Calculate the hourly consumption in kWh.
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When the lift is moving upwards, the weight being raised is 5 ton + 0.5 ton and a weight of 2 ton which is the counterweight is being lowered. The load is raised through a height of 50 m.
The work to be done is m*g*h,
m*g*h = (5.5 - 2)* 9.8 * 50 KJ
(The entire section contains 141 words.)
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