If an average minimum daily requirement for calcium is 1150 mg. what percentage of your daily reqirements woul be met my drinking 1.0 L of your local water containing 361.68 mg of calcium

Expert Answers
jerichorayel eNotes educator| Certified Educator

To get the percent of calcium taken by drinking 1.0 L of the local water, you can use this formula. 

Amount of calcium taken / average daily calcium requirement x 100

Drinking 1.0 of the local water would give you 361.68 mg so the percent of calcium you have taken in that day would be:

361.68/1150 x100 = 31.450 % = 31.5% calcium taken

This means that you are below the minimum calcium intake and therefore you should drink more water and/or eat food with significant amount of calcium in it. 

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