When an object is viewed through a telescope we are looking at the light emitted from it. As light travels the intensity decreases in an inverse square law relationship. An object that is twice is far away is going to appear 1/4 as bright as the light has spread over...

## Unlock

This Answer NowStart your **48-hour free trial** to unlock this answer and thousands more. Enjoy eNotes ad-free and cancel anytime.

Already a member? Log in here.

When an object is viewed through a telescope we are looking at the light emitted from it. As light travels the intensity decreases in an inverse square law relationship. An object that is twice is far away is going to appear 1/4 as bright as the light has spread over 4 times the distance. The path of light traveling from a point is in the shape of a cone.

The diameter of the human eye is 0.5 cm. If an object that is being viewed has to be brightened 16900 times, we need to collect light over an area that is 16900 times as large as the area of the human eye and focus it on to the area of the human eye.

This would require using a lens with diameter. `0.5*sqrt(16900)` = 0.5*130 = 65

If the light from an object is collected by a lens that has a diameter 65 cm and focused on the eye, it would ideally appear 16900 times as bright.