An aluminum nail has a charge of 3.2x10^-6C. How many electrons must be added to the nail to make it electrically neutral?pls provide equation thx
We can basically say that:
`(t otal charg e)/(charg e -per -el ectron) = n umber of el ectrons`
one coulomb = `6.24151x10^18` electrons therefore one electron has a charge of `1.602x10^(-19)` coulombs.
So to get the total number of electrons, we just divide the given charge of the aluminum nail by the charge of one electron.
`n umber of el ectrons = (3.2x10^(-6) C)/(1.602x10^(-19)C/e)`
`= 1.998x10^(13) el ectrons`
Provide the final answer with the right significant figures.
`2.0 x10^13` electrons -> final answer