An aircraft preparing for  take-off accelerates uniformly from 0 m/s to 20 m/s in a time of 5 s. What is the acceleration of the aircraft?

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If the initial velocity of an aircraft is u and it accelerates at a rate of acceleration a for a time t, the final velocity v is given by v = u + at

Here, u = 0 m/s, v = 20 m/s and t = 5 s, substituting these...

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If the initial velocity of an aircraft is u and it accelerates at a rate of acceleration a for a time t, the final velocity v is given by v = u + at

Here, u = 0 m/s, v = 20 m/s and t = 5 s, substituting these in the equation given earlier.

20 = 0 + a*5

=> a = 20/5 = 4 m/s^2

The acceleration of the aircraft is 4 m/s^2

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You need to use the equation .  In this case, v = 20.0m/s, Vo= 0m/s and t=5.00s.  Using these numbers, we get... 

a = (V - Vo)/ t

a=20.0 / 5 which works out to a = 4.0m/s

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