In an acid-base titration, 42.90 mL of 0.825 M H2SO4 was required to neutralize 75.0 mL of NaOH solution. What is the molarity of the NaOH solution?

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jeew-m | College Teacher | (Level 1) Educator Emeritus

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`H_2SO_4+2NaOH rarr Na_2SO_4+2H_2O`

Mole ratio;

`NaOH:H_2SO_4 = 2:1`

Amount of `H_2SO_4` consumed `= 0.825/1000xx42.9 = 0.0354mol`

Amount of NaOH reacted `= 2xx0.0354 = 0.0708mol`

If the molarity of NaOH is X;

`X/1000xx75 = 0.0708`

`X = 0.944M`

So the molarity of NaOH is 0.944mol/L

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