# i am trying to solve a specific heat equation and i cant figure out which variables go with which givens? or what im trying to solve for.

*print*Print*list*Cite

The specific heat equation is Q = m*c*`Delta`T

**Q = heat**

m = mass

**c = specific heat**

`Delta` T = change in temperature

From a message, we are given:

"suppose you have a 2.000 lb block of iron at 50.0°C. **How much heat in Joules** would it take to warm this block to 75.0°C?" So the mass is 2.000 lbs, the change in temp is 25.0°C but I don't understand what the heat and specific heat are?

So, **we are looking for Q**. We have the mass and delta T. **So, we need the specific heat. That is specific to the material, like density. This is iron. The specific heat of iron is 0.45 kJ/kg degC**. We have the delta T in Celsius. **We need the 2000 lbs. in kg.** Using Google's conversion for pounds to kg, 2000 pounds = 907.1847 kg. So, plugging in the numbers:

Q = m*c*delT

= 907.1847*0.45*25

= 10,205.827875 kJ = 10,205,827.875 joules.