Find the time when the balloon hits the ground. Answer in complete sentences. Marvin was standing on the roof of his house throwing water balloons onto people on the sidewalk below. When he let the balloon go the balloon was 45 cubits off of the ground. He learned through trial and error that in order to hit someone on the ground he had to have the balloon reach a maximum height of 55 cubits off of the ground 2 seconds after he threw it. Let h(t) be the height of the water balloon in cubits t seconds after it was thrown. Assume that height is a quadratic function of time. a) Find formula for h(t) b) Find the time when the balloon hits the ground. Answer in complete sentences.

Expert Answers

An illustration of the letter 'A' in a speech bubbles

For this question we can think about what we know:
At the starting time, the balloon is released at 45 cubits in height
After 2 seconds it reaches a maximum of 55 cubits off the ground

PART A) We want to write a formula h(t) to represent the height od the balloon at a given time called t. There are different equations for quadratics, one being standard form of y=ax^2 + bx + c, and one being vertex form, or y = a(x-h)^2 + k. Because we know the maximum height and time it took to get there, we have the information to plug in for the vertex (h,k) = (2, 55). Let's plug that into the vertex form formula, but we'll use t and h(t) instead of x and y:

(The entire section contains 358 words.)

Unlock This Answer Now

Start your 48-hour free trial to unlock this answer and thousands more. Enjoy eNotes ad-free and cancel anytime.

Start your 48-Hour Free Trial
Approved by eNotes Editorial Team