Al den is 12 feet longer than it is wide. If the den's area is 405 square feet, what are the dimensions of the room? (_,_)?

llltkl | Student

Let, width of the room be x feet

Then its length = (x+12) feet

According to the given problem:

den's area = 405 square feet

`rArr x*(x+12)=405`






`=(-12+-42)/2` =30/2=15 or -54/2=-27

Since dimensions cannot be negative, we get x=15

width=15 feet and length=(15+12) or 27 feet.

Therefore, the dimensions of the room are width=15 feet, length=27 feet