First, diagram out the problem. I have it attached. It never says anything about up/down, North/South, etc., only the angles. So, we have that. From that, we can use the law of sines to find the distance for airplane B:

`sin(45)/x = sin(50)/20`

Cross multiplying:

`20*sin 45 = x*sin 50`

`20*sin(45)/sin(50) = x`

x = 18.46 miles

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