Again, I have to ask a question...
I fee like I'm giving you my all homework but... this website is my only way to understand and learn something! (I guess, people who answer my questions and explaine to me, do it better than my teacher...)
3 Answers | Add Yours
There are a couple of ways to "consider" factoring these. They stem from:
y = ax^2 + bx + c
The general form for a quadratic equation, the form your equation is written in, with:
a = 1. b = -2, and c = -15
I will assume your teacher is working with the "easier method" first, when a = 1.
You are looking for two parenthesis of the form when you factor this:
(x + #)(x + #), both numbers can be different, even positive and negative.
When a = 1, then the method calls for trying to determine 2 numbers that multiply to c but add to b. So, in this case:
two number that multiply to -15 and add to -2
Start considering all the factors for -15:
There are no other pairs of numbers. The question, which pair of numbers, when you add them together, gives you -2? The -5 and 3:
-5*3 = -15
-5 + 3 = -2
So, from there, you just plug them into (x+#)(x+#):
x^2 - 2x - 15 = (x + -5)(x + 3) = (x - 5)(x + 3)
So, we have:
y = (x - 5)(x + 3)
To find the horizontal intercepts, or the x intercepts, you are setting each parenthesis = 0 and solving for x:
x-5 = 0 and x + 3 = 0
So, x = 5 and -3
So, the graph would cross the x axis at (5,0) and (-3,0)
The equation `h(z)=z^2-2z-15` is easily factored. Two factors of 15 with a difference of 2 are: 5 and 3. Since the second coefficient is negative, then the 5 has to be negative to get both coefficients to be negative. The factored function is `h(z)=(z+3)(z-5)`
I infer from the second half of the question that they mean h(z)=y and z=x, and the horizontal intercepts are the x-intercepts i.e. where the graph of the function crosses the x-axis or y=0 There are exactly two coordinates where this happens, and in the ascending order of x values they are (-3,0) and (5,0).
You can verify by plugging the first number of each ordered pair in for z and finding that the computed value for h(z) is 0 (the second number in each ordered pair).
Thank you to both of you for your fast answer!
I will go for SteveSchoen's answer as it is the most complete and gives me the "How to" process. I need the answers for my homeworks but I absolutely need to know how to do it for future exercice and exams.
I will make it a PDF right away! Thank you Steve!
The funy thing is that I have that in my notes but.... as my teacher just come in class and give us a huge BlaBla for 50 min, write on the board and leave... when I come home, I just know that I spent 50 min writting letters and numbers... and I'm still at level 0.
I envy the class that is before me. The teacher make them work as groups on exercices.
We’ve answered 318,988 questions. We can answer yours, too.Ask a question