# Adult tickets cost \$4 and children tickets cost \$1. 285 tickets are sold. And \$765 is collected. How many adult tickets were sold.? Use substitution or elimination to solve the problem If adult tickets cost \$4, and children's tickets cost \$1, and 285 tickets total were sold, and the total amount collected is \$765, there can only be one possible answer. I believe you will find that 160 adult tickets were sold (total of \$640) and 125 children's tickets were sold...

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If adult tickets cost \$4, and children's tickets cost \$1, and 285 tickets total were sold, and the total amount collected is \$765, there can only be one possible answer. I believe you will find that 160 adult tickets were sold (total of \$640) and 125 children's tickets were sold (total of \$125). Combining these two amounts will give you 285 tickets and a total of \$765. Any difference in tickets sold by either adults or children would result in a higher or lower total amount.

Approved by eNotes Editorial Team The answer to this is that 160 adult tickets were sold.  This means that 125 children's tickets were sold.  Here is how to solve this problem:

Let's call adult tickets A and children's tickets C.

We know that A + C = 285 because that's how many total tickets were sold.

We know that 4A + C = 765.  That's because each adult ticket sold cost \$4 so 4 times the number of adult tickets, plus the number of kids tickets (\$1 each) make the total amount collected.

Let's use the first equation to find for C.  C = 285 - A.

Now just substitute that into the other equation and you have

4A + 285 - A = 765.

3A = 480

A = 160

Approved by eNotes Editorial Team