# According to one model of bird flight, the power consumed by a pigeon flying at velocity `v` (in m/s) is `P(v)=17v^-1 +10^-3*v^3` . Find the velocity that minimizes power consumption. The function is obviously defined only for `v gt 0` and is continuously differentiable on this interval. When `v` approaches zero the function tends to `+oo,` when v tends to `+oo,` the function also tends to `+oo.`

Thus it must have at least one local (and global) minimum and it is reached at the point(s) where `P'(x) = 0.`  Let's solve this equation:

`P'(x) = -17 v^-2 + 3*10^-3*v^2 = 0.`

This is equivalent to  `17 v^-2 = 3*10^-3*v^2,` or  `v^4 = 17/3*10^3.`

The only solution is  `v = root(4)(17/3*10^3) approx`  8.7 (m/s). This is the answer.

Approved by eNotes Editorial Team Take the derivative of `P(v)` .

`P'(v)=-17v^-2+3*10^-3v^2`

Set `P'(v)` equal to zero and solve for the critical values.

`-17v^-2+3*10^-3v^2=0`

`-17+3*10^-3v^4=0`

`3*10^-3v^4=17`

`v^4=17/3*10^3`

`v^4=17/3*10^3`

`v=(17/3*10^3)^(1/4)~~8.676 m/s`

We can check graphically that this is indeed a minimum.