# Acceleration is sometimes expressed in multiples of g, where g=9.8 m/s^2 is the acceleration due to the earth's gravity. In a car crash , the car's velocity may go from 26 m/s to 0 m/s in 0.15 s....

Acceleration is sometimes expressed in multiples of g, where g=9.8 m/s^2 is the acceleration due to the earth's gravity. In a car crash , the car's velocity may go from 26 m/s to 0 m/s in 0.15 s. How many g's are experienced , on average , by the driver?

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### 1 Answer

In the car crash, the car's velocity could go from 26 m/s to 0 m/s in 0.15 s.

The magnitude of the acceleration of the car is (26 - 0)/0.15 = 520/3 m/s^2

In terms of the acceleration due to gravity equal in magnitude to 9.8 m/s^2, this is approximately equal to 17.68g

**The acceleration of the car is approximately equal to 17.68g**