The acceleration of a particle moving in a straight line is given by a(t) = 6(t-3).   Given that particle’s initial velocity is 24 units per second, during the time interval 0 less than or equal to t is less than or equal to 5, find (a) The average acceleration.

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The average aceeleration is the value of the acceleration over the time interval from 0 to 5 is given by:

`av={a(5)-a(0)}/{5-0}`

`={6(5-3)-6(0-3)}/5`

`={12+18}/5`

`=6`

The average acceleration over the interval is 6 units squared per second.

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