The acceleration of a particle moving in a straight line is given by a(t) = 6(t-3). Given that particle’s initial velocity is 24 units per second, during the time interval 0 less than or equal to t is less than or equal to 5, find (a) The average acceleration.

Expert Answers

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a(t) = 6(t-3)

 

At t = 0

a(0) = 6*-3 = -18

 

At t = 5

a(5) = 6(5-3) = 12

 

Change in acceleration in 5 seconds = a(5)-a(0) = 12-(-18) = 30

 

Average acceleration = 30/5 = 6


So the average acceleration is 6m/s^2

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