How much force is exerted by the atmosphere on 10.8 km^2 of land at sea level?

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The pressure acting on a surface is determined by the force acting on a unit area of the surface. At sea level the standard pressure exerted by the atmosphere or 1 atm = 101325 Pa.

Pascal is a unit of pressure in terms of the force in newton and the...

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The pressure acting on a surface is determined by the force acting on a unit area of the surface. At sea level the standard pressure exerted by the atmosphere or 1 atm = 101325 Pa.

Pascal is a unit of pressure in terms of the force in newton and the surface area in m^2.

The force exerted by the atmosphere on a surface area equal to 10.8 km^2 can be determined by first converting 10.8 km^2 to a value in m^2.

10.8 km^2 = 10.8/(1000)^2 m^2. As the pressure exerted is 101325 Pa, 101325 = F/10.8*10^-6

=> F = 101325*10.8*10^6 N

=> F = 1094310*10^6 N

The force exerted by the atmosphere on 10.8 km^2 of land at sea level is 1094310*10^6 N

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