This is an example of projectile motion. A projectile can be thought of as an object which is thrown with a certain velocity and whose motion is then only governed by the force of gravity. The projectile can be thrown vertically or at an angle like the golf ball or a cricket ball.

The horizontal distance traveled by a projectile is termed as the Range and is given by the following equation:

Range = `(V^2 sin 2theta )/g`

where V is the initial velocity with which the projectile is thrown, `theta` is the angle with the horizontal made by the projectile and "g" is the acceleration due to the gravity.

Here, the initial velocity is 40 m/s, angle made with the horizontal is 50 degrees, and using a value of 9.81 m/s^2 for acceleration due to gravity on the surface of Earth, we can calculate the range of the golf ball as:

Range = [40^2 sin 2(50)]/9.81 = 160.62 m

Thus, the golf ball (assuming no bounce or roll) will land 160.62 m from the point where it started from. Since the hole was 170 m away from the starting point, the ball land a distance of 170 - 160.62 = **9.38 m short of the hole**.

Other parameters, such as the maximum height reached, time of flight, etc. can also be calculated by using the appropriate equations of projectile motion.

Hope this helps.

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