-8v-10=-3(2v-2)

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kingattaskus12's profile pic

kingattaskus12 | (Level 3) Adjunct Educator

Posted on

To determine the value of v in the given equation, we must apply the distibutive property of multiplication to the right side of the equation first. This gives

`-8v-10=-3(2v-2)`

`-8v-10=-6v+6`

Then if group like terms, we have

`-8v+6v=6+10`

`-2v=16`

`v=-8`

sciencesolve's profile pic

sciencesolve | Teacher | (Level 3) Educator Emeritus

Posted on

You need to solve for variable v the given linear equation, hence, you first need to perform the multiplication to the right side, such that:

`-8v - 10 = -6v + 6`

You need to isolate the terms that contain the variable v to the left side, such that:

`-8v + 6v = 10 + 6 => -2v = 16 => v = 16/(-2) => v = -8`

Hence, evaluating the variable v, yields `v = -8.`

sid-sarfraz's profile pic

sid-sarfraz | Student, Graduate | (Level 2) Salutatorian

Posted on

QUESTION:-

-8v-10=-3(2v-2)

SOLUTION:-

We have solve for the value of v, hence;

-8v - 10 = -3(2v-2)

Open the bracket of RHS first by multiplying 3 to both values;

-8v - 10 = -6v + 6

Bring -6v on LHS and -10 On RHS, changing signs of both of them;

-8v + 6v = 6 + 10

-2v = 16

Divide both sides by -2;

-2v/(-2) = 16/(-2)

v = -8

Hence the answer is v= -8

malkaam's profile pic

malkaam | Student, Undergraduate | (Level 1) Valedictorian

Posted on

-8v - 10 = -3(2v - 2)

To find the value of the unknown variable v, we need to isolate it,

-8v - 10 = -3(2v - 2)

-8v - 10 = -6v + 6

-8v - 10 + 10 = -6v + 6 + 10          Add 10 to both sides

-8v = -6v + 16

-8v + 6v = -6v + 16 + 6v                Add 6v to both sides

-2v = 16

-2v/-2 = 16/-2                               Divide both sides by -2

v = -8 Answer.

If you want to check the answer you can input the value in the above equation and see if they balance, in which case the answer will be correct.

 
nisarg's profile pic

nisarg | Student, Grade 11 | (Level 1) Valedictorian

Posted on

-8v-10=-3(2v-2)

-8v-10=-6v+6

-8v+6v-10=6

-2v-10=6

-2v=16

v=-8

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