You need to solve for variable v the given linear equation, hence, you first need to perform the multiplication to the right side, such that:

`-8v - 10 = -6v + 6`

You need to isolate the terms that contain the variable v to the left side, such that:

`-8v + 6v = 10 + 6 => -2v = 16 => v = 16/(-2) => v = -8`

**Hence, evaluating the variable v, yields **`v = -8.`

To determine the value of v in the given equation, we must apply the distibutive property of multiplication to the right side of the equation first. This gives

`-8v-10=-3(2v-2)`

`-8v-10=-6v+6`

Then if group like terms, we have

`-8v+6v=6+10`

`-2v=16`

`v=-8`

**QUESTION:-**

**-8v-10=-3(2v-2)**

**SOLUTION:-**

We have solve for the value of v, hence;

-8v - 10 = -3(2v-2)

Open the bracket of RHS first by multiplying 3 to both values;

-8v - 10 = -6v + 6

Bring -6v on LHS and -10 On RHS, changing signs of both of them;

-8v + 6v = 6 + 10

-2v = 16

Divide both sides by -2;

-2v/(-2) = 16/(-2)

v = -8

Hence the answer is v= -8

-8v - 10 = -3(2v - 2)

To find the value of the unknown variable v, we need to isolate it,

-8v - 10 = -3(2v - 2)

-8v - 10 = -6v + 6

-8v - 10 + 10 = -6v + 6 + 10 Add 10 to both sides

-8v = -6v + 16

-8v + 6v = -6v + 16 + 6v Add 6v to both sides

-2v = 16

-2v/-2 = 16/-2 Divide both sides by -2

**v = -8 Answer.**

If you want to check the answer you can input the value in the above equation and see if they balance, in which case the answer will be correct.