If the square of a number is between 25 & 48, then the number is between ? and ?
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To put your question in maths terms:
Let x= the number
`25<x^2<48` as it cannot =25 or it cannot =48 if it is between them.
As `sqrt(25) =...
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(1) -> Given: square of a number is between 25 - 48
Solution :
Case 1: If the number is a positive integer then it will be between
Intger(square root of(25)) and Integer(square root of (49))
since 48 is not a perfect square and the next perfect square is 49.
Hence the number will be between 5 and 7 <-- Answer
Case 2:If the number is an (+) or (-) integer then it will be between
-5 and 7 <--Answer
[ since square root of 25 is (+5) and (-5)
Case 3:If the number is positive real number then it will be between
5.0 and 6.928
Case 4:If the number is a (+) or (-) real number then it will be
between -6.928 and +6.928 <-- Answer
Q2) There are 7 numbers which are perfect square including 1 and 54
[ they are : 1, 4, 9, 16, 25, 36, 49 ] therefore there are 7 ways
by which any one of the number picked will be a perfect square and
there are 54 ways by which any number 1 - 54 (both inclusive) can be
picked. Therefore probability of a number picked random will be a
perfect square = 7/54 = 0.129 <-- Answer
Q3) Every positive number >1 is greater than its square root
example : square root of 4 = (+2) and (-2) [4>2, 4>-2]
Similarly square root of 9 = (+3) and (-3) [ 9>3, 9>-3]
And the square root 1 is equal to 1
Hence we can say that Every number is greater than or equal to
its square root
From the example given we can also say the counter that is :
Square root of Every positive number is less than or equal to the
number
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