Let us say the solution is X.

Amount of X at the start `= 1.6/1000xx72 = 0.1152mol`

This 0.1152 mol will be diluted until the volume become 278ml.

So now we have 0.1152 moles of X in 278ml of solution. Assume the the moles of X are equally distributed over the solution.

Then we separate 139ml of the above solution.

Amount of X in 139ml `= 0.1152/278xx139 = 0.0576mol`

So we have 0.0576 moles of X of X in 139ml of the solution. Then we add 155ml of water.

Final volume of the solution `= 155+139 = 294ml`

So final mixture we have 0.0576moles of X diluted in 294ml solution.

Concentration of final mix `= 0.0576/294xx1000 = 0.1959M`

*So the concentration of the final mixture is 0.1959M.*

**Further Reading**

## We’ll help your grades soar

Start your 48-hour free trial and unlock all the summaries, Q&A, and analyses you need to get better grades now.

- 30,000+ book summaries
- 20% study tools discount
- Ad-free content
- PDF downloads
- 300,000+ answers
- 5-star customer support

Already a member? Log in here.

Are you a teacher? Sign up now