`7 [sqrt(m+1) - 3] = 21` I need to find a way to solve (for m): `7 [sqrt(m+1)- 3] = 21`  

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`7(sqrt(m+1)-3) = 21`

`sqrt(m+1)-3 = 21/7`

`sqrt(m+1)-3 = 3`

`sqrt(m+1) = 6`

Get the power of 2 in both sides.

`(sqrt(m+1))^2 = 6^2`

`m+1 = 36`

   ` m = 35`

 

So the answer is m = 35.

 

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