# A 7 kg object undergoes an acceleration of 1.8 m/s^2.What is the magnitude of the resultant force acting on it? Answer in units of N. If this same force is applied to a 4.4kg object, what...

A 7 kg object undergoes an acceleration of 1.8 m/s^2.

What is the magnitude of the resultant force acting on it? Answer in units of N.

If this same force is applied to a 4.4kg object, what acceleration is produced? Answer in units of m/s^2.

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This question is answered using Newton's Second Law

F = m a

where F is the applied force, m is the mass, and a is the acceleration. Using the mass and acceleration given in the question, we find that the force is

F = ( 7 kg ) ( 1.8 m/s^2 ) = 12.6 kg m/s^2

Now we can use that force and the second mass to find the acceleration

a = F / m = 12.6 kg m/s^2 / 4.4 kg = 2.86 m/s^2

Since the first mass is given to only one significant figure, our result must be expressed in the same manner, so the final answer is

a = 3 m/s^2

Force = mass* acceleration or

F=m*a

The force required to generate 1.8m/s^2 in a mass of 7 kg object =7* 1.8= 12.6 N

The force on the second object is 12.6N and its mass =4.4 kg.

Therefore, the equation, force =mass*aceeleration gives us:

12.6N=4.4kg*a . So, a =12.6N/4.4kg = 2.8636 m/s^2 nearly.

Therefore, the acceleration produced in the object of mass of 4.4kg by the force 12.6 N is 2.8636 m/s^2