grumpybear -- You know how to do the distributive property I would assume . . so you will use it to get rid of the paratheses in the problem.

Is there anything in front of the first set of ()'s? This would make them a little unneccessary . . so...

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grumpybear -- You know how to do the distributive property I would assume . . so you will use it to get rid of the paratheses in the problem.

Is there anything in front of the first set of ()'s? This would make them a little unneccessary . . so just drop them.

Now in front of the second set is only a - . . .think of this as a -1 (because there is always an invisible 1 if there is nothing in that spot, right?) So, distribute the -1 into the second set of ()'s. Now you will have . . .

6x - 8 - 5x - 9 = 3 --> *{-1(5x) + -1(9) = -5x - 9}*

from here, combine like terms (x's with other x's & #'s with other #'s) on the same side of the equal sign.

6x - 5x = 1x or just x *(there's the invisible 1 again)*

-8 - 9 = -17

so . .

x - 17 = 3 This is looking a little easier to handle right!

+17 +17 add 17 to both sides to cancel it from the x

x = 20

Distributing the negative problems (like this one) can be a little tricky. Remember to check your answers to make sure you are right . . .use your calculator to make it quick and easy to check . . .

(6*20 - 8) - (5*20 + 9) = ?

(112) - (109) = 3