600.0mL of air is at 20.0 degrees Celsius. What is the volume at 60.0 degrees Celsius?
As you stated in your tag words, this question deals with Charles' Law. This law states that the volume of a gas is directly proportional to its temperature assuming that the pressure and the number of moles of gas remains constant. In other words:
V = kT
where V is the volume, T is the temperature, and k is the proportionality constant. If you are comparing two different sets of temperatures and volumes, you can set up the proportionality like below to eliminate the need for the constant k:
`(V1)/(T1) = (V2)/(T2)`
Now we can simply input the three given values and solve for the unknown. Please note that volume needs to be in units of liters and temperature in units of Kelvin (which is the number in Celsius plus 273):
`(0.600 L)/(293 K) = (V2)/(333 K)`
V2 = 0.6*333/293 = 0.682 L = 682 mL
So the answer is the volume is equal to 682 mL.