# If the 60 kg player is running forward at 7.0 m/s when she makes contact with the dummy, what is the player’s velocity at the end of the 1.20 s impact? Please can somebody tell me I am doing...

**If the 60 kg player is running forward at 7.0 m/s when she makes contact with the dummy, what is the player’s velocity at the end of the 1.20 s impact? **

**Please can somebody tell me I am doing it right!!**

Impulse can be calculated using either equation:

**Fnet (difference Time)=(difference P(momentum)) or **

**Fnet ( difference Time)=m x (difference velocity)**

**If mass m is constant, then the only quantity changing on the right-hand side of the equation is V(velocity). So the equation becomes:**

**Fnet (difference Time)=m x (difference Velocity)**

**Given I= -360Ns , m=60kg, V initial=7.0 m/s**

**I impulse = m x (vf - vi)**

**Vf = 1.0 m/s**

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