`6^x + 10 = 47` Solve the exponential equation algebraically. Approximate the result to three decimal places.

Textbook Question

Chapter 3, 3.4 - Problem 22 - Precalculus (3rd Edition, Ron Larson).
See all solutions for this textbook.

1 Answer | Add Yours

Educator Approved

Educator Approved
loves2learn's profile pic

loves2learn | (Level 3) Salutatorian

Posted on

Subtract 10 from both sides

`6^x=37 `

Take the ln of both sides

`ln(6^x)=ln37 `

Bring down the exponent

`xln6=ln37 `

`x=ln37/ln6 `

`x=2.015 `

We’ve answered 318,994 questions. We can answer yours, too.

Ask a question