# `6^x + 10 = 47` Solve the exponential equation algebraically. Approximate the result to three decimal places.

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Student Comments

loves2learn | Student

Subtract 10 from both sides

`6^x=37 `

Take the ln of both sides

`ln(6^x)=ln37 `

Bring down the exponent

`xln6=ln37 `

`x=ln37/ln6 `

`x=2.015 `