A 55 kg block of granite has an original temperature of 15.0 C. Look below for the rest of the question.What will be the final temperature of this granite if 4.5x10^4kJ of heat energy are added to...

A 55 kg block of granite has an original temperature of 15.0 C. Look below for the rest of the question.

What will be the final temperature of this granite if 4.5x10^4kJ of heat energy are added to the granite?

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krishna-agrawala | College Teacher | (Level 3) Valedictorian

Posted on

Given:

Wieight of granite block = w = 55 kg

Initial temperaturee of granite block = ti = 15.0 degrees C

Heat energy added = h = 4.5x10^4 kJ = 45000

We know specific heat of Granite = s = 0.79 kJ/kg/decree C

Therefore rise in temprrature of the granite block is gioven by:

h/(s*w)

Therefore:

Final temperature of block = tf = ti + h/(s*w)

Substituting the actual valuse on abobe equation we get:

tf = 15.0 + 45000/(0.79*55) = 15.0 + 1035.67 = 1050.67 degrees C

Answer:

Final temperature of granite block will be 1050.67 degrees C

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