A 50 N force is applied at the end of 30 cm wrench.If force makes an angle of 67° with wrench,what is the mangitude of torque about point of rotation?
The torque created by a force that is applied is equal to T = f*d*sin x, where f is the force applied, d is the distance between the point where the torque is being measured to where the force is being applied and x is the angle between the displacement vector of the line joining the point where the force is applied to the point where torque is being measured and the force vector.
In the problem a force of 50 N is applied at a distance of 0.3 m from the point where torque is measured and the angle made is 67 degrees. This gives the torque as T = 50*0.3*sin 67 = 13.80 N*m
The magnitude of the torque due to the force is 13.80 N*m