# 5(x-6)=20

violy | High School Teacher | (Level 1) Associate Educator

Posted on

First way to solve this:

Use Distributive Property `a(b+c)=a*b+a*c` to the left side.

`5(x-6)=20`

`5*x+5*-6=20`

`5x-30=20`

Since, we need to solve for x, we must isolate the term with x on one side.

Therefore, we must get rid of the 30 that is being subtracted on left side.

To do that, since 30 is being subtracted we will use the opposite operation of subtraction. So, add 30 on each side.

`5x-30+30=20+30`

`5x=50`

Now, we must get rid of the 5 on left side. So, we will use the opposite operation of multiplication, which is division. Divide 5 on each side.

`(5x)/(5) = (50)/(5)`

We know that 5 will be cancel on left side.

`x = 10`

That is it! :)

Another method can be used to solve this.

We can get rid of the 5 on left side by dividing 5 on each side.

`(5(x-6))/(5)=(20)/(5)`

`x-6=4`

Second Way to solve this:

Isolate the x on left side, since 6 is being subtracted on left side,

use the opposite operation of subtraction which is addition. Add 6 on each side.

`x - 6 + 6 = 4 + 6`

`x = 10`

That is it! :)

aishukul | Student, Grade 10 | (Level 3) Honors

Posted on

To solve this, you isolate x and use the distributive property.

5(x-6)=20. When you multiply 5 by x and multiply 5 by -6 also, you use the distributive property.

5x-30=20. Then you add 30 to the other side of the equation.

5x=50. Then divide by 5 on both sides.

x=10. This is the final answer.

malkaam | Student, Undergraduate | (Level 1) Valedictorian

Posted on

5(x - 6) = 20

The main thing to be done is to isolate x, to find it's value.

The first step is to apply the distributive property,

5(x - 6) = 20

5x - 30 = 20

5x - 30 + 30 = 20 + 30        Add 30 to both sides

5x = 50

5x/5 = 50/5                         Divide both sides by 5

ssandhu05 | Student, Undergraduate | (Level 2) Honors

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The first step to solving this problem is by distributing the 5 to the x and -6. This results in 5x-30=20. Next, you want to add 30 on both sides. We're trying to get the x by itself, so that is why. The result of adding 30 is 5x=50. Now, to get x by itself, we divide 5 on either side to get x=10.

udonbutterfly | Student, College Freshman | (Level 1) Valedictorian

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I presume we are looking for the value of x

5(x-6)=20

so first we are going to distribute the 5 to the equation in the parentheses so you will get...

5x -30 =20

Now you are going to add 3 on both sides

30+ 5x -30 =20 + 30 The 30 cancels out from the left side

5x = 50 Now divide 5 on both sides and you have your answer!

5x/5 = 50/5

x=10 In order to check to see if your answer is right just plug 10 in as x of the original equation

5(10-6)=20 Solve in the parentheses first

5(4)=20 multiply 5 by 4

20=20 Since they are the same on both sides 10 is definitely the answer!

sid-sarfraz | Student, Graduate | (Level 2) Salutatorian

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Question:-

5(x-6)=20

Solution:-

5(x-6) = 20

5 * x - 5 * 6 = 20

5x - 30 = 20

5x = 20 + 30

5x = 50

x = 50/5

x = 10

Hence solved!

jsuleiman123 | Elementary School Teacher | (Level 1) Adjunct Educator

Posted on

5(x-6)=20

First we must get x by itself on one side of the equation.

So, first divide each side by 5.

5(x-6)/5= 20/5

This cancels out the 5 and you end up with (x-6)=4

Finally, to cancel out the -6, we'll add 6 to both sides.

x-6+6=4+6

x+o=10 or

x=10