5/6·1/2+2/3÷4/3 How do I solve this problem?
You would set this problem up as an order of operations problem.
First you eliminate parentheses
Second you eliminate exponents
Third you multiply and divide in order from left to right
Fourth you add and subtract in order from left to right.
Here is a sentence to help you remember what to do first.
Please excuse my dear Aunt Sally.
(parentheses) exponents multiply and divide add and subtract
reorder terms (when dividing fractions use the reciprocal of the second fraction and multiply them)
multiply fractions (you could cross multiply)
add fractions (be sure that the denominator for both fractions is the same, and add the numerators)
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The first thing you want to do is follow the orders of operation some people call it PEMDAS.
First put parenthesis around where the fractions are
Now first multiply (5/6) by (1/2) and you will get 0.4167 or (5/12)
Now you're going to divide (2/3) by (4/3) and you will get 0.5 or (1/2)
Then you will have an equation like this 0.4167 + 0.5 or (5/12) + (1/2)
Adding them up will now get you 0.9167 or 11/12