A 5.0 µC point charge is moved within an electric field and has an electric potential energy change of 10.0 J. What is the electric potential difference before and after the charge was moved? Show your work. (µC = 1.0 × 10–6 C)

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The change of potential energy of a charge is the charge times the potential difference:

`Delta U = q*DeltaV`

So, the potential difference is

`Delta V = Delta U/q = 10 J/(5 muC) = 2*10^6 V = 2MV` (megavolts)

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