`4u^2 - 1 = 0` Solve the equation.

Textbook Question

Chapter 5, 5.2 - Problem 13 - McDougal Littell Algebra 2 (1st Edition, Ron Larson).
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rsarvar1a | Student, Grade 9 | (Level 1) Honors

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4u^2 - 1 = 0

4u^2 - 1 + 1 = 0 + 1

4u^2 = 1

4u^2 / 4 = 1 / 4

u^2 = 1/4

sqrt(u^2) = sqrt(1/4)

u = 1/2, -1/2

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iamkaori | Student, Grade 9 | (Level 2) Salutatorian

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4u^2 - 1 = 0

Bring the -1 over to get:

4u^2 = 1

Divide both side by 4 to get:

u^2 = 1/4

Square root both sides to get the u as itself:

u = `+- 1/2`

Thus, `u = 1/2, -1/2`

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