`4sin^3 (x) + 2sin^2 (x) - 2sin(x) - 1 = 0` Use a graphing utility to approximate the solutions (to three decimal places) of the equation in the interval `0,2pi)`.

1 Answer

gsarora17's profile pic

gsarora17 | (Level 2) Associate Educator

Posted on

See the attached graph

Solutions in the given interval are,

`x=pi/4 , (3pi)/4, (5pi)/4 , (7pi)/4 , (7pi)/6 , (11pi)/6`

`x~~0.800 , 2.300 , 3.600 , 3.900 , 5.500 , 5.800`

Images:
This image has been Flagged as inappropriate Click to unflag
Image (1 of 1)
Sources: