48=x(x+6)
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You need to open the brackets to the right side such that:
`48 = x^2 + 6x`
You should move all terms to the left side such that:
`48 - x^2 - 6x = 0`
Multiplying by -1 and arranging the terms with respect to power of variable x yields:
`x^2 + 6x - 48 = 0`
Using quadratic formula yields:
`x_(1,2) = (-b+-sqrt(b^2-4ac))/(2a)`
You need to identify the coefficients a,b,c such that:
`a=1 , b = 6 , c = -48`
`x_(1,2) = (-6+-sqrt(36+192))/2 => x_(1,2) = (-6+-sqrt228)/2`
`x_(1,2) = (-6+-2sqrt57)/2 => x_(1,2) = (-3+-sqrt57)`
Hence, evaluating the solutions to the given quadratic equation yields `x_(1,2) = (-3+-sqrt57).`
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48=x^2+6x
x^2+6x-48=0
Using the quadratic formula, x=4.55 or x=-10.55
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