# If 4^(3x^2 - 18) = 8 what is x.

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### 1 Answer

The equation `4^(3x^2 - 18) = 8` has to be solved for x.

`4^(3x^2 - 18) = 8`

=> `2^(2*(3x^2 - 18)) = 2^3`

=> `2^(6x^2 - 36) = 2^3`

Equate the exponent and solve for x.

`6x^2 - 36 = 3`

=> `6x^2 - 39 = 0`

=> `x^2 = 13/2`

=> `x = +- sqrt(13/2)`

**The solution of the equation is **`x = +- sqrt(13/2)`