Expert Answers
sciencesolve eNotes educator| Certified Educator

You need to solve for x the quadratic equation, hence, you should use quadratic formula, such that:

`x_(1,2) = (-b+-sqrt(b^2 - 4ac))/(2a)`

Identifying coeficients a,b,c, yields:

`a = 3, b =12, c = 39`

`x_(1,2) = (-12+-sqrt(12^2 - 4*3*39))/(2*3)`

`x_(1,2) = (-12+-sqrt(144 - 468))/6`

`x_(1,2) = (-12+-sqrt(-324))/6`

Since the problem does not specify the nature of the solutions to equation, hence, you may also consider complex roots, such that:

`x_(1,2) = (-12+-18*i)/6`

Notice that complex number theory states that `sqrt(-1) = i.`

`x_(1,2) = (-2+-3*i)`

Hence, evaluating the complec solutions to the given quadratic equation, yields `x_(1,2) = (-2+-3*i)` .

oldnick | Student



`x^2+4x +4+9=0`





indeed   `Delta= 16- 4 xx 13= 16-52=-36 <0`

So has two complex coniugate roots