`3x + 1 - sin(x) = 0` Use the Intermediate Value Theorem and Rolle’s Theorem to prove that the equation has exactly one real solution.

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Chapter 3, 3.2 - Problem 67 - Calculus of a Single Variable (10th Edition, Ron Larson).
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Borys Shumyatskiy | College Teacher | (Level 3) Associate Educator

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Consider f(x)=3x+1-sinx. This function is continuous and infinitely differentiable on `RR`.

`f(0)=1gt0` and `f(-pi)=1-3pilt0.`

By the Intermediate Value Theorem there is at least one `c in (-pi, 0)` for which `f(c)=0.` So our equation has at least one solution.

If it has one more solution, by Rolle's Theorem there is `c_1` between roots such that `f'(c_1)=0.` But `f'(x)=3-cosx,` which is always >0. This contradiction proves that there is only one root.

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